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November 21, 2014

November 21, 2014

Posted by **Jasmine** on Thursday, April 19, 2012 at 12:00am.

- calculus -
**Steve**, Thursday, April 19, 2012 at 12:22pmsince the pool is a rectangular solid, it has a cross-section of constant size.

the pool is 15x40 = 600 ft^2

Thus, each ft of depth adds 600ft^3 of volume.

So, at 25ft^3/min, the height rises 25/600 = .0417 ft/min

Now, since this is for calculus class, they must want a solution involving related rates.

v = 40*15*x = 600x when the water is x feet deep.

dv/dt = 600 dx/dt

25 = 600 dx/dt

dx/dt = 25/600 = .0417

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