Iron (III) sulfate is a yellow compound that is used as a coagulant in water treatment. write a balance chemical equation and a solubility product expression for its dissolution in water.

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Fe2(SO4)3(s) <--> 2Fe3+ (aq) + 3SO4^2-(aq)

ksp = [Fe3+]2 [SO4^2-]3

is that right? ^

yes

To write the balanced chemical equation for the dissolution of Iron (III) sulfate in water, we need to understand the chemical formula of Iron (III) sulfate and how it dissociates in water.

The chemical formula for Iron (III) sulfate is Fe2(SO4)3. In water, it dissociates into its respective ions:

Fe2(SO4)3(s) → 2Fe3+(aq) + 3SO4^2-(aq)

Writing the balanced chemical equation:
Fe2(SO4)3(s) → 2Fe3+(aq) + 3SO4^2-(aq)

Now, let's move on to writing the solubility product expression for Iron (III) sulfate.

The solubility product expression relates to the equilibrium between the dissolved ions and undissolved solid. The solubility product expression for Iron (III) sulfate is given by multiplying the concentrations of the ions raised to their respective powers.

For Iron (III) sulfate, the solubility product expression is:

Ksp = [Fe3+]^2[SO4^2-]^3

Here, [Fe3+] represents the concentration of Fe3+ ions in the solution, and [SO4^2-] represents the concentration of SO4^2- ions in the solution.

Please note that the solubility product constant (Ksp) represents the equilibrium constant for the dissolution of the solid compound in water.