Electronic types neglect the force of gravity on electrons.To see why, compute the force of Earth's gravity on an electron and compare it with the force exerted on the electron by an electric field of magnitude 6000 V/m (a relatively small field). The mass of an electron is 9.1 * 10-31 kg and the charge of an electron is 1.6 * 10-19
I came up with 5.7*10^-12 and it marked me wrong.....HELP!!
I can vouch it is probably wrong...
force electric= Eq= 6000*1.6E-19=9.6E-16M
force gravity= GMe m/re^2=9.8N/kg * 9.1E-31kg=8.9E-30 N
Now the ratio of Fgravaity/Felectric=
= 8.9E-30/8.9E-3=1E-27 which is significantly different than yours. Recheck your and my work.
GOT IT THANKS ..FINALLY
1.1*10^14
To compute the force of Earth's gravity on an electron, you can use the formula for gravitational force:
F_gravity = m * g
Where:
F_gravity is the force of gravity
m is the mass of the electron
g is the acceleration due to gravity (approximately 9.8 m/s^2)
Given:
m = 9.1 * 10^-31 kg
Calculating the force of gravity on the electron:
F_gravity = (9.1 * 10^-31 kg) * (9.8 m/s^2)
F_gravity = 8.92 * 10^-30 N
Now let's calculate the force exerted on the electron by an electric field of magnitude 6000 V/m. The force exerted by an electric field on a charged particle can be calculated using the formula:
F_electric = q * E
Where:
F_electric is the force exerted by the electric field
q is the charge of the electron
E is the magnitude of the electric field
Given:
q = 1.6 * 10^-19 C
E = 6000 V/m
Calculating the force exerted by the electric field:
F_electric = (1.6 * 10^-19 C) * (6000 V/m)
F_electric = 9.6 * 10^-16 N
Comparing the two forces, you can see that the force of gravity on the electron (8.92 * 10^-30 N) is much smaller than the force exerted by the electric field (9.6 * 10^-16 N). Therefore, it is often neglected in electronic systems.
To solve this problem, let's start by calculating the force of gravity on the electron and the force exerted by the electric field.
1. Force of gravity on the electron:
The force of gravity can be calculated using Newton's law of universal gravitation:
Fgravity = m * g
Where:
Fgravity is the force of gravity
m is the mass of the electron
g is the acceleration due to gravity (approximately 9.8 m/s^2)
Given:
m = 9.1 * 10^(-31) kg
Substituting these values into the formula, we get:
Fgravity = (9.1 * 10^(-31) kg) * (9.8 m/s^2)
Fgravity ≈ 8.9 * 10^(-30) N
2. Force exerted on the electron by the electric field:
The force exerted on a charged particle by an electric field can be calculated using the equation:
Felectric = q * E
Where:
Felectric is the force exerted by the electric field
q is the charge of the electron
E is the magnitude of the electric field
Given:
q = 1.6 * 10^(-19) C
E = 6000 V/m
Substituting these values into the formula, we get:
Felectric = (1.6 * 10^(-19) C) * (6000 V/m)
Felectric = 9.6 * 10^(-16) N
Now let's compare the two forces:
Fgravity ≈ 8.9 * 10^(-30) N
Felectric = 9.6 * 10^(-16) N
From the calculation, we can see that the force exerted by the electric field is much larger than the force of gravity on the electron. Therefore, it is not unreasonable for electronic types to neglect the force of gravity on electrons when compared to the forces exerted by electric fields.
If you obtained a different result (5.7 * 10^(-12)), please double-check your calculations to ensure correct multiplication and unit conversions.