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posted by Bob on Wednesday, April 18, 2012 at 6:58pm.

Assume that an average SNMP response message is 100 bytes long. Assume that a manager sends 40 SNMP Get commands each second. What percentage of a 128 kbps WAN link would the response message represent?

100 byte IP packet takes 18 byte ethernet overhead + 20 byte of "silence" inter frame gap = 40 * 138 * 8 bps = 44160 bps = 0,4% of BW of a 100 Mbps link

That is correct my friend. I just did mine and aced it. :)

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