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Posted by on Wednesday, April 18, 2012 at 5:44pm.

A 190 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.160 m/s. How much work must be done on the hoop to stop it?

  • Physics - , Wednesday, April 18, 2012 at 6:32pm

    W =KE = m•v^2/2 + I•ω^2/2 =
    = m•v^2/2 +(mR^2) •(v^2/R)/2= mv^2 =
    =190•0.16^2 =4.86.4 J

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