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December 27, 2014

December 27, 2014

Posted by **Josh** on Wednesday, April 18, 2012 at 3:33pm.

tan(A+B); cosA=-1/7, A in quadrant 3, sinB=1/2, B in quadrant 2.

- Pre-Calc help NOW PLEASE!!! -
**Steve**, Wednesday, April 18, 2012 at 4:43pmin Q3, tan is positive, so tanA = √48

in Q2, tan is negative, so tanB = -1/√3

Now apply the addition formula

tan(A+B) = (tanA+tanB)/(1-tanA tanB)

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