Saturday

April 19, 2014

April 19, 2014

Posted by **Joe** on Wednesday, April 18, 2012 at 2:50pm.

How far (in terms of A) is this mass from the equilibrium position of the spring when the elastic potential energy equals the kinetic energy?

- Physics -
**Elena**, Wednesday, April 18, 2012 at 5:56pmx=A•sinωt

v =dx/dt = A•ω•cosωt

PE = KE

kx^2/2 = mv^2/2

k = m•ω^2

m•ω^2• (A•sinωt)^2/2 = m•( A•ω•cosωt)^2/2

(sinωt)^2 = (cosωt)^2

(tan ωt)^2 = 1

ωt = π/4

x=A•sinωt = A•sin(π/4) =0.707•A

**Related Questions**

PHYSICS - HELP - Two ingenious 120 student students decide to use an ...

physics - Damped mass spring system oscillates at 205 Hz. The time constant of ...

physics - A damped mass-spring system oscillates at 190 Hz. The time constant of...

PHYSICS - HELP - Two ingenious 120 student students decide to use an oscillating...

PHYSICS - Two ingenious 120 student students decide to use an oscillating mass ...

PHysics - What is the total energy of a 15-kg mass attached to a spring ...

physics - A mass is oscillating with amplitude A at the end of a spring. How far...

Physics - A block has mass 800 g, whose is fasten to a spring with spring ...

Physics ( Damped Oscillations ) - A 3-kg mass attached to a spring with k = 142 ...

Physics ( Dammed Oscillations ) - A 3-kg mass attached to a spring with k = 142 ...