Posted by **zuhra** on Wednesday, April 18, 2012 at 2:38pm.

A sealed container contains 1 mole of neon gas at STP. Estimate the number of neon atoms having speeds in the range from 200 m/s to 202 m/s. (Hint: Assume the probability of neon atoms having speeds between 200 m/s and 202 m/s is constant).

- physics -
**Elena**, Wednesday, April 18, 2012 at 5:33pm
STP - Standard Temperature and Pressure - is 273 and 105 Pa

Maxwell distribution for the relative velocities is

ΔN/N = 4/sqrt(π)(1/e^(u^2))u^2Δu,

v1 = 200m/s, v2 =202 m/s, Δv =202-200 = 2m/s.

The most probable velocity

v(pr) = sqrt(2RT/M) = sqrt(28.31273/2010^-3) = 476.3 m/s.

The relative velocity is

u = v1/v(pr) = 200/476.3 = 0.42,

u^2 = 0.176,

1/e^(u^2)) = 0.838

Δu = Δv/v(pr) = 2/476.3 = 4.210^-3.

ΔN/N = 4/sqrt(π)0.8380.1764.210^-3 =1.410^-3 = 0.0014.

Therefore. 1,4% of the neon atoms have the velocities of 200 202 m/s or their absolute number in 1 mole is

ΔN = N0.0014 = 6.02210^230.0014 = 8.4210^20

- physics -
**Erica**, Sunday, April 14, 2013 at 11:20pm
This looked a little sloppy imo... Here's my example

1. Find most probably velocity of Krypton

v = √[(2*8.314J/K*273K)/(0.083798 kg)] = 237.75 m/s

Find the ratio of each velocity

205/237.75 = .8808 The average is .8851

207/237.75 = .8894

Find the ratio of change in velocities 207-205

2/237.75 = 0.008593

Then: Find the probability!

6.022e23 molecules * 5 mol * .8851 * 0.008593 = 2.29e22

I just did a problem like this... These are my numbers, but the work is a lot more simple

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