Question

Factor the expression 64a^2-16ab+b^2 into a product of binomials

Answer 1

Use the AC method.

A*C = 64(1) = (-8)(-8).
64a^2 + (-8ab-8ab) + b^3 =
Arrange the 4 terms to form 2 factorable pairs:
(64a^2-8ab)) + (-8ab+b^2) =
-8a(-8a+b) + b(-8a+b) =
(-8a+b)(-8a+b).