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March 2, 2015

March 2, 2015

Posted by **Lueshelle** on Wednesday, April 18, 2012 at 1:22pm.

- intermediate algebra -
**Henry**, Thursday, April 19, 2012 at 11:18pmUse the AC method.

A*C = 64(1) = (-8)(-8).

64a^2 + (-8ab-8ab) + b^3 =

Arrange the 4 terms to form 2 factorable pairs:

(64a^2-8ab)) + (-8ab+b^2) =

-8a(-8a+b) + b(-8a+b) =

(-8a+b)(-8a+b).

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