Posted by jonathan on .
a 7 foot tall man is standing 65 feet away from a tower. if the angle of elevation is 35 degrees. what is the height of the tower to nearest tenth of a foot?

trig 
Steve,
If there are h feet of tower above the man's eyes, h/65 = tan35°
so, the tower height is 7 + 65tan35° = 52.5 ft