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August 28, 2014

August 28, 2014

Posted by **sandra** on Wednesday, April 18, 2012 at 10:52am.

- pre-cal -
**Steve**, Wednesday, April 18, 2012 at 11:23amcenter midway between vertices at (3,2)

slope of asymptote 2/3 = a/b

(y-2)^2/4 - (x-3)^2/9 = 1

- pre-cal -
**sandra**, Saturday, April 21, 2012 at 4:45amthank you very much

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