Friday

April 18, 2014

April 18, 2014

Posted by **sandra** on Wednesday, April 18, 2012 at 10:10am.

can someone show me this graph(x+2)^2/4+(y+2)^2/15=1

- Pre-cal -
**Steve**, Wednesday, April 18, 2012 at 11:30amwolframalpha . com can. Just enter

plot (x+2)^2/4+(y+2)^2/15=1

Hyperbola with center at (-2,-2), eccentricity = √15/2

- Pre-cal - PS -
**Steve**, Wednesday, April 18, 2012 at 11:31amoops

ellipse, semi-major axes 2 and √15

major axis parallel to y-axis

- Pre-cal -
**sandra**, Saturday, April 21, 2012 at 4:44amthank you

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