Monday

March 30, 2015

March 30, 2015

Posted by **Anonymous** on Wednesday, April 18, 2012 at 8:39am.

At this instant, calculate the resultant linear acceleration, in m/s^2, of a point on the circumference of the flywheel.

- Physics -
**Elena**, Wednesday, April 18, 2012 at 12:21pmω = 10.44rad/s ,

ε = 51.57rad/s^2

R =D/2.

Normal (centripetal) acceleration

a(n) = ω^2•R.

Tangential acceleration

a(τ) = ε•R.

Resultant linear acceleration

a =sqrt(a(n)^2 + a(τ)^2).

**Answer this Question**

**Related Questions**

kinematics - An exercise bicycle's flywheel is 30cm in diameter and 2.5 cm thick...

kinetics - An exercise bicycle's flywheel is 30cm in diameter and 2.5 cm thick ...

kinetics - An exercise bicycle's flywheel is 30cm in diameter and 2.5 cm thick ...

kinetics - An exercise bicycle's flywheel is 30cm in diameter and 2.5 cm thick ...

kinetics - An exercise bicycle's flywheel is 30cm in diameter and 2.5 cm thick ...

engineering mechanics - An exercise bicycle's flywheel is 30cm in diameter and 2...

engineering mechanics - An exercise bicycle's flywheel is 30cm in diameter and 2...

Angular acceleration - A flywheel of 480 mm diameter is accelerated with an ...

physics - The flywheel of a steam engine runs with a constant angular velocity ...

PHYSICS!!! - The flywheel of a steam engine runs with a constant angular ...