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Analytical Chemistry

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How many millimoles and molecules of solute are in 500 ml of a solution that is 5.41 ppm KMnO4?

  • Analytical Chemistry - ,

    5.41 ppm = 5.41 mg/L.
    5.41 mg/L x 0.5L = ?mg
    ?mg x (1 g/1000 mg) = ? g
    mols = g/molar mass = ?
    Multiply by 1000 to convert to millimols.

    For number of molecules, remember that 1 mol contains 6.022E23 molecules. Use that with the number of mole from above.

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