Homework Help: physics

Posted by Allan on Wednesday, April 18, 2012 at 5:59am.

A source of instantaneous potential V = 10sin(50pi t) is connected across a capacitor of capacitence 1 times 10power negative 6 F. calculate the maximum value of the current and phase difference between the current and the potential difference?

physics - Elena, Wednesday, April 18, 2012 at 1:44pm
V = 10sin(50π t),
V(max) = 10 V,
C =1•10^-6 F,
q(max) = V(max)•C = 10•1•10^-6 =
= 10^-5 (Coulomb)
q = q(max)•sin(50π t) =
=10^-5•sin(50πt) (Coulomb)
I = dq/dt = 10^-5•50π•cos(50πt) (A),
I(max) = 10^-5•50π =1.57•10^-3 A.

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