posted by Allan on .
A source of instantaneous potential V = 10sin(50pi t) is connected across a capacitor of capacitence 1 times 10power negative 6 F. calculate the maximum value of the current and phase difference between the current and the potential difference?
V = 10sin(50π t),
V(max) = 10 V,
C =1•10^-6 F,
q(max) = V(max)•C = 10•1•10^-6 =
= 10^-5 (Coulomb)
q = q(max)•sin(50π t) =
I = dq/dt = 10^-5•50π•cos(50πt) (A),
I(max) = 10^-5•50π =1.57•10^-3 A.