A white-crowned sparrow flying horizontally with a speed of 1.65 m/s folds its wings and begins to drop in free fall.
(a) How far does the sparrow fall after traveling a horizontal distance of 0.550 m?
(b) If the sparrow's initial speed is increased, does the distance of fall increase, decrease, or stay the same?
physics - Steve, Wednesday, April 18, 2012 at 12:03pm
time to cover .550m = .550m / 1.65m/s = 1/3 s
distance fallen in 1/3 s = 4.9 * (1/3)^2 = 0.54m
since s(t) = Vo*t + 1/2 at^2, if its initial speed changes, its distance does so in like manner. Think about it. If you throw a rock down, it will fall farther than if you just drop it.
physics - PS - Steve, Wednesday, April 18, 2012 at 12:04pm
Oops. Since the sparrow's speed is given as horizontal, it will fall the same vertical distance no matter how fast it is going horizontally.