Posted by **chanz11** on Wednesday, April 18, 2012 at 5:00am.

the velocity of a particle traveling in a straight line is given by v=(6t-3t^2)m/s, where t is in seconds, if s=0 when t= 0. determine the particles deceleration and position when t=3s. how far has the particle traveled during the 3s time interval and what is its average speed?

- math(mechanics) -
**Reiny**, Wednesday, April 18, 2012 at 8:00am
if v = 6t - 3t^2

then a = 6 - 6t

and s = distance = 3t^2 - t^3 + c , where c is a constant.

but we are told that s-0 when t= 0 , so c = 0

when t = 3

a = 6 - 6(3) = - -12

s = 3(3^2) - 3^3 = 0

total distance = final position - initial position

= 0 - 0 = 0

avg speed = 0/3 = 0

## Answer this Question

## Related Questions

- math(mechanics) - the acceleration of a particle as it moves along a straight ...
- Dynamics - A particle moving along a straight line is subjected to a ...
- math(mechanics) - a particle moves along a straight line such that its position ...
- Calculus (Derivatives) - Two particles are moving in straight lines. The ...
- amet - PART A 1. The acceleration of a body along a straight line is given by (a...
- calculus - a particle moves along a number line measured in cm so that its ...
- physics,dynamics - The acceleration of a particle along a straight line is ...
- math - The acceleration am/s^2 of a particle moving in a straight line is given ...
- math - For 4.95 seconds , a particle moves in a straight line according to the ...
- math - For 4.95 seconds , a particle moves in a straight line according to the ...