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September 30, 2014

September 30, 2014

Posted by **chanz11** on Wednesday, April 18, 2012 at 5:00am.

- math(mechanics) -
**Reiny**, Wednesday, April 18, 2012 at 8:00amif v = 6t - 3t^2

then a = 6 - 6t

and s = distance = 3t^2 - t^3 + c , where c is a constant.

but we are told that s-0 when t= 0 , so c = 0

when t = 3

a = 6 - 6(3) = - -12

s = 3(3^2) - 3^3 = 0

total distance = final position - initial position

= 0 - 0 = 0

avg speed = 0/3 = 0

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