Posted by chanz11 on Wednesday, April 18, 2012 at 4:56am.
the acceleration of a particle as it moves along a straight line is given by a=(2t1)m/s^2, where t is in seconds.if s=1m and v= 2m/s when t=0,determine the particles velocity and position when t=6s. Also, determine the total distance the particle travels during this time period.

math(mechanics)  Reiny, Wednesday, April 18, 2012 at 8:03am
a = 2t  1
then v = t2  t + c
when t = 0, v = 2
2 = c
then v = t^2  t + 2
s = (1/3)t^3  (1/2)t^2 + 2t + k
when t = 0 , s = 1
1 = k
s = (1/3)t^3 + (1/2)t^2 + 2t + 1
plug in t=6 to get your results.