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math(mechanics)

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the acceleration of a particle as it moves along a straight line is given by a=(2t-1)m/s^2, where t is in seconds.if s=1m and v= 2m/s when t=0,determine the particles velocity and position when t=6s. Also, determine the total distance the particle travels during this time period.

  • math(mechanics) -

    a = 2t - 1
    then v = t2 - t + c
    when t = 0, v = 2
    2 = c
    then v = t^2 - t + 2

    s = (1/3)t^3 - (1/2)t^2 + 2t + k
    when t = 0 , s = 1
    1 = k

    s = (1/3)t^3 + (1/2)t^2 + 2t + 1

    plug in t=6 to get your results.

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