Posted by Liz on Tuesday, April 17, 2012 at 9:54pm.
f = x√t(x-1)/(x+2)
f' = [(x√(x-1))'(x+2) - x√(x-1)(1)]/(x+2)^2
= [{√(x-1) + x/2√(x-1)}(x+2) - x√(x-1)]/(x+2)^2
= (x^2+6x-4)/(2√(x-1)(x+2)^2)
wolframalpha . com will show you the steps for almost any derivative you can throw at it.
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