Posted by LILY on Tuesday, April 17, 2012 at 3:07pm.
You must be Mily from below.
same thing as before
∫ t^5 dt from t=21 to t=x
= (1/6)t^6 from t-21 to t=x
= (1/6)x^6 - (1/6)(21)^6
= (1/6)(x^6 - 21^6)
what about f ' (x)?
i did with (1/6)(x^6-21^6) but its wrong
f(x)=∫(21,x) t^5
f'(x)= x^5
i font know
but thanks
i got it, it correct answer is f'(x)=-x^5.
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