Posted by **LILY** on Tuesday, April 17, 2012 at 3:07pm.

If f(x)= ∫(21,x) t^5 dt then f'(x).

my answer was 1/6 (21^6-x^6) it said it's wrong.

- college Calculus Help! -
**Reiny**, Tuesday, April 17, 2012 at 3:29pm
You must be Mily from below.

same thing as before

∫ t^5 dt from t=21 to t=x

= (1/6)t^6 from t-21 to t=x

= (1/6)x^6 - (1/6)(21)^6

= (1/6)(x^6 - 21^6)

- college Calculus Help! -
**LILY**, Tuesday, April 17, 2012 at 3:55pm
what about f ' (x)?

i did with (1/6)(x^6-21^6) but its wrong

f(x)=∫(21,x) t^5

f'(x)= x^5

i font know

- college Calculus Help! -
**LILY**, Tuesday, April 17, 2012 at 4:04pm
but thanks

- college Calculus Help! -
**LILY**, Tuesday, April 17, 2012 at 4:25pm
i got it, it correct answer is f'(x)=-x^5.

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