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March 27, 2015

March 27, 2015

Posted by **Alan** on Tuesday, April 17, 2012 at 2:34pm.

- Calculus -
**Reiny**, Tuesday, April 17, 2012 at 3:40pm(1/2)(xy)^(-1/2) (x dy/dx + y) = 1 - 2dy/dx

at the given point

(1/2)(4)^(-1/2) (4dy/dx + 1) = 1 - 2dy/dx

(1/4)(4dy/dx + 1 = 1 - 2dy/dx

times 4

4dy/dx + 4 = 1 - 2dy/dx

6dy/dx = -3

dy/dx = -1/2

y-1 = -(1/2)(x-4)

2y-2= -x+4

x + 2y = 6

or

y = (-1/2)x + 6

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