WHAT DOES A 138 N ROCK WEIH IF IT IS ACCELERATING UPWARD AT 12 M/S DOWNWARD AT3.5 M/S . C WHAT WOULD BE THE ANSWERS TO PARTS (A)AND (B) IF THE ROCK HAD A MASS OF138 Kg WHAT WOULD BE THE ANSWERS TO PARTS A AND B IF THE ROCK WERE MOVING WITH A CONSTANT UPWARD VELOCITY OF 23 M/S?
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To answer the given question, let's break it down into parts.
Part (A): What is the net force acting on the rock when it accelerates upward at 12 m/s^2?
To find the net force, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a): F = m * a.
Given:
- Mass of the rock (m) = 138 kg
- Acceleration (a) = 12 m/s^2 (upward)
Substituting the values into the formula, we get:
F = 138 kg * 12 m/s^2
Calculating the product:
F = 1656 N
Therefore, the net force acting on the rock when it accelerates upward at 12 m/s^2 is 1656 N.
Part (B): What is the net force acting on the rock when it accelerates downward at 3.5 m/s^2?
Using the same formula, let's solve for Part (B):
Given:
- Mass of the rock (m) = 138 kg
- Acceleration (a) = 3.5 m/s^2 (downward)
Substituting the values into the formula, we get:
F = 138 kg * (-3.5 m/s^2) (Note: The negative sign indicates the opposite direction)
Calculating the product:
F = -483 N
Therefore, the net force acting on the rock when it accelerates downward at 3.5 m/s^2 is -483 N.
Now, let's move on to the second part of the question.
Part (A): If the rock had a mass of 138 kg and a constant upward velocity of 23 m/s, what is the net force acting on it?
When the rock is moving with a constant velocity, the net force acting on it is zero. This is based on Newton's first law of motion, which states that an object at rest or in motion at a constant velocity will continue to do so unless acted upon by an external force.
So, in this case, if the rock has a mass of 138 kg and a constant upward velocity of 23 m/s, the net force acting on it would be zero.
Part (B): Similarly, if the rock is moving with a constant upward velocity of 23 m/s, the net force acting on it would still be zero, as there is no acceleration involved.
In summary:
- Part (A): Net force = 0 N (when the rock has a constant upward velocity of 23 m/s)
- Part (B): Net force = 0 N (when the rock has a constant upward velocity of 23 m/s)