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posted by tony on Monday, April 16, 2012 at 11:55pm.

how many rectangles can have the perimiter of 46m

P = 2 W + 2 L P = 2 ( W + L ) 46 = 2 ( W + L ) Divide both sides by 2 46 / 2 ) = 2 ( W + L ) / 2 23 = W + L W + L = 23 For integers : W = 1 m L = 22 m W = 2 m L = 21 m W = 3 m L = 20 m etc.

math

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