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How would you find the pH of a solution prepared by mixing 50 mL of 0.125 M KOH with o.050 L of 0.125 M HCl?

  • Chemistry -

    mols KOH = M x L = ?
    mols HCl = M x L = ?
    Determine which is in excess, the
    pH = -log(H^+) if HCl is in excess
    pOH = -log(OH^-) if KOH is in excess.
    pH = 7 if neither is in excess.

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