posted by Anne .
How would you find the pH of a solution prepared by mixing 50 mL of 0.125 M KOH with o.050 L of 0.125 M HCl?
mols KOH = M x L = ?
mols HCl = M x L = ?
Determine which is in excess, the
pH = -log(H^+) if HCl is in excess
pOH = -log(OH^-) if KOH is in excess.
pH = 7 if neither is in excess.