What is the vertex of y=(x-2)^2 +5?
To find the vertex of a quadratic function in the form y = a(x-h)^2 + k, where (h, k) represents the coordinates of the vertex, follow these steps:
Step 1: Identify the values of h and k in the equation. In this case, the given equation is y = (x-2)^2 + 5. We can see that h = 2 and k = 5.
Step 2: The vertex of the quadratic function is represented by the coordinates (h, k). Therefore, the vertex is (2, 5).
So, the vertex of the quadratic function y = (x-2)^2 + 5 is (2, 5).