Posted by Grace on Monday, April 16, 2012 at 7:17pm.
pH = 4.0; (H^+) = 1E-4
............HA ==> H^+ + A^-
initial....0.1......0.....0
change.....-x........x.....x
equil....0.1-x.......x.....x
x = 1E-4
Ka = (H^+)(A^-)/(HA)
Substitute from the ICE chart and solve for Ka.
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