what mass of ethanol(C2H5OH) will be required to prepare a 2.00m solution in 8.00kg of water?
m = 2 mols/kg solvent
Solve for mols
moles = grams/molar mass
You have mole from above and molar mass, solve for grams.
what mass of ethanol(C2H5OH) will be required to prepare a 2.00m solution in 8.00kg of water?
Calculate the volume required to dissolve 11.2 g of CuSO4 to prepare a 0.140M solution
what mass of ethanol will be required to prepare a 2.00m solution of in 8.00kg of water
To calculate the mass of ethanol required to prepare a 2.00 M solution in 8.00 kg of water, we can use the formula:
moles of solute = concentration × volume of solution in liters
We know the concentration (2.00 M), and we can assume a volume of 8.00 L (since the density of water is 1 kg/L).
First, we can calculate the number of moles of solute required:
moles of C2H5OH = 2.00 mol/L × 8.00 L = 16.0 mol
Next, we can use the molar mass of ethanol (46.07 g/mol) to convert the moles of ethanol to grams:
mass of C2H5OH = 16.0 mol × 46.07 g/mol = 737 g
Therefore, we would need 737 grams of ethanol to prepare a 2.00 M solution in 8.00 kg of water.
To find the mass of ethanol required to prepare a 2.00m solution in 8.00kg of water, we need to calculate the amount of ethanol needed in moles and then convert it to grams.
First, let's determine the moles of ethanol required using the formula:
moles = concentration × volume (in liters)
Since we want to prepare a 2.00m (molar) solution, the concentration is 2.00 mol/L. However, we don't know the volume of the solution yet, so let's find it.
To prepare a solution, we need the total mass of the solution, which includes both the solvent (water) and the solute (ethanol).
Total mass of solution = mass of water + mass of ethanol
Given that the mass of water is 8.00 kg, we can convert it to grams:
mass of water = 8000 grams
Now, to find the mass of ethanol, we subtract the mass of water from the total mass of the solution:
mass of ethanol = total mass of solution - mass of water
Since we don't know the total mass of the solution, we can calculate it indirectly from the desired concentration and volume using the equation:
total mass of solution = (mass of solute ÷ concentration) + mass of solvent
In this case, the mass of solute is the mass of ethanol, the concentration is 2.00 mol/L, and the solvent is water. Remember that 1 liter of water has a mass of 1000 grams.
Now, let's solve for the volume of the solution:
volume = (total mass of solution - mass of water) ÷ density of water
The density of water is approximately 1 gram/mL, so the volume can be found in mL or L.
Finally, we can calculate the moles of ethanol using the equation mentioned earlier:
moles of ethanol = concentration × volume
To find the mass of ethanol, we use the molar mass of ethanol, which is 46.07 g/mol.
mass of ethanol = moles of ethanol × molar mass of ethanol
By following these calculations, we can determine the mass of ethanol required to prepare the 2.00m solution in 8.00kg of water.