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November 28, 2014

November 28, 2014

Posted by **Yvonne** on Monday, April 16, 2012 at 2:14pm.

- College Math -
**Steve**, Monday, April 16, 2012 at 3:42pmIf you start with amount P, then after t years, R, the fraction remaining, is

R = 2^(-t/5730)

See how that works? Every 5730 years, the power of 2 goes down by 1.

2^(-t/5730) = .88

-t/5730 = ln(.88)/ln(2) = −0.321928095

t = 5730 * 0.321928095

t = 1844.64798435

or, to the nearest 100 years, 1800.

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