Posted by **Alex** on Monday, April 16, 2012 at 12:07pm.

Ice of mass 11.0 kg at 0.00° C is placed in an ice chest. The ice chest has 3.00 cm thick walls of thermal conductivity 1.00 10-5 kcal/s · m · C° and a surface area of 1.25 m2.

(a) How much heat must be absorbed by the ice before it melts?

(b) If the outer surface of the ice chest is at 29.0° C, how long will it take for the ice to melt?

- physics -
**Elena**, Monday, April 16, 2012 at 2:12pm
Q = r•m =335000•11 = 3.685•10^6 J,

where r is the heat of fusion.

q = α•(ΔT/Δx)•A,

where q is the heat flow per unit time,

α is åðó thermal conductivity,

α =1•10^5 kcal/s • m • C° =

=0.041868 J/s • m • C°,

ΔT is the temperature driving force,

Δx is the thickness of the walls,

and A is the surface area,

q = 0.041868•(29/0.03) •1.25 =

=50.59 J/s.

t = Q/q = 3.685•10^6/50.59 = 7.28•10^4 s = 20.23 h.

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