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September 18, 2014

September 18, 2014

Posted by **Michael** on Monday, April 16, 2012 at 10:50am.

- Calculus -
**Steve**, Monday, April 16, 2012 at 10:59amif you let u = 9+3x, du = 3dx and you have

∫√(9+3x) dx = ∫√u (du/3) = 1/3 ∫u^(1/2) du

take it from there.

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