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September 19, 2014

Posted by **Dalcy** on Monday, April 16, 2012 at 9:09am.

- maths -
**Reiny**, Monday, April 16, 2012 at 9:53amnumber of pennies --- p

number of nickels ---- n

number of dimes ---- 13-p-n

p + 5n + 10(13-p-n) = 83

p + 5n + 130 - 10p - 10n = 83

-9p - 5n= -47

9p + 5n = 47 ---> n = (47-9p)/5

since both p and n have to be positive integers

0 < p < 5 and 0 < n< 10

try p=1 , n is a fraction

p = 2, n is a fraction

p=3 , n = 4

p = 4 , n is a fraction

so p = 3, n = 4 and subbing back, dimes = 6

check" 3(1) + 4(5) + 6(10) = 83

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