Posted by **Dalcy** on Monday, April 16, 2012 at 9:09am.

a box containing pens,nickels,and dimes has 13 coins with a total value of 83 cents.how many coins of each type are in the box?

- maths -
**Reiny**, Monday, April 16, 2012 at 9:53am
number of pennies --- p

number of nickels ---- n

number of dimes ---- 13-p-n

p + 5n + 10(13-p-n) = 83

p + 5n + 130 - 10p - 10n = 83

-9p - 5n= -47

9p + 5n = 47 ---> n = (47-9p)/5

since both p and n have to be positive integers

0 < p < 5 and 0 < n< 10

try p=1 , n is a fraction

p = 2, n is a fraction

p=3 , n = 4

p = 4 , n is a fraction

so p = 3, n = 4 and subbing back, dimes = 6

check" 3(1) + 4(5) + 6(10) = 83

## Answer this Question

## Related Questions

- math - There are 60 coins in a box containing only nickels, dimes, and quarters...
- math - Mr. Adams has a box containing 14 coins. The coins are either quarters, ...
- math - Three coins are selected from 10 coins: 4 dimes, 4 nickels, and 2 ...
- Grade 5 Maths - A coin box contained some twenty-cent and fifty-cent coins in ...
- maths - A coin box contained some twenty-cent and fifty-cent coins in the ratio ...
- Math - A change purse contains an equal number of pennies, nickels, and dimes. ...
- Math - rick has a box of coins. The box contains 51 coins. Which consist of ...
- math - When a child breaks open her piggy bank, she finds a total of 76 coins, ...
- Maths algebra 1 - Janella has only quarters dimes and pennies in her pocket ...
- Math problem I need help with - Combination of coins that can be used; fifty-...