A toy rocket is shot vertically from the base of a multiple level parking garage. the rockets height in feet is modeled by the equation h(T)= -16T squared+ 128 T, where T is the time in seconds if the rocket just reaches the top of the parking garage, how high is the parking garage, and how long does it take the rocket to reach this height?
physics - drwls, Monday, April 16, 2012 at 12:02am
Maximum height is reached when the velocity dh/dT = -32T + 128 = 0
That happens at T = 4.0 seconds.
Use the h(T) equation to calculate the height at that time.
h(max) = -16*(4^2) + 128*4 = 256 feet