Homework Help: Chemistry 1201

Posted by John on Sunday, April 15, 2012 at 11:21pm.

Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is
2C4H10(g)+13O(g)-> 8CO2(g)+10H2O(l)

At 1.00 atm and 23C , what is the volume of carbon dioxide formed by the combustion of 3.40 grams of butane?

PV=nRT or n=PV/RT
R=0.08206

Chemistry 1201 - DrBob222, Sunday, April 15, 2012 at 11:31pm
You made a typo on the equation. You omitted the 2 on O2.
mols butane = 3.40g/molar mass C4H10 = ?
Convert mols C4H10 to mols CO2 using the coefficients in the balanced equation.
Use PV = nRT to convert mols CO2 to volume in L.
Chemistry 1201 - John, Sunday, April 15, 2012 at 11:38pm
Thanks so much!

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