Posted by Pamela on Sunday, April 15, 2012 at 11:07pm.
radio active radium(226)
Let P be the initial amount
n be the years
A the amount remaining after n years
A = P*(1/2)^(n/1599)
A/P = (1/2)^(n/1599)
so, the % remaining is
100*(1/2)^(n/1599)
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