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October 1, 2014

October 1, 2014

Posted by **Pamela** on Sunday, April 15, 2012 at 11:07pm.

- Calc -
**Pamela**, Sunday, April 15, 2012 at 11:11pmradio active radium(226)

- Calc -
**Steve**, Monday, April 16, 2012 at 12:24amLet P be the initial amount

n be the years

A the amount remaining after n years

A = P*(1/2)^(n/1599)

A/P = (1/2)^(n/1599)

so, the % remaining is

100*(1/2)^(n/1599)

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