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April 1, 2015

April 1, 2015

Posted by **Keya** on Sunday, April 15, 2012 at 9:52pm.

Integral 1 to infinity of e to the power of (-1/2).

- Calculus -
**bobpursley**, Sunday, April 15, 2012 at 10:27pmYou integral does not make a lot of sense to me. e^(-1/2) is a constant, no variable.

INT 1/sqrte dx from 1 to inf is

1/sqrte * (infinity-1)

I suspect you meant something else.

- Calculus -
**Keya**, Sunday, April 15, 2012 at 10:46pmsorry if i was not clear. it is

INT 1/sqrt e (the constant) dy from 1 to infinity.

Determine if it is convergent or divergent

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