Posted by Jason on Sunday, April 15, 2012 at 9:09pm.
A private medical clinic wants to estimate the true mean annual income of its patients. The clinic needs to be within $100 of the true mean. The clinic estimates that the true population standard deviation is around $2,100. If the confidence level is 95%, find the required sample size in order to meet the desired accuracy.

Statistics  MathGuru, Monday, April 16, 2012 at 4:45pm
Use a formula to find sample size.
Here is one:
n = [(zvalue * sd)/E]^2
...where n = sample size, zvalue will be 1.96 using a ztable to represent the 95% confidence interval, sd = 2100, E = 100, ^2 means squared, and * means to multiply.
Plug the values into the formula and finish the calculation. Round your answer to the next highest whole number.
Hope this helps.

Statistics  Anonymous, Friday, September 21, 2012 at 10:16pm
A population is normally distributed with mean 26.8 and standard deviation 2.5. Find p( 26.8 < x < 29.3 ). (Round your answer to FOUR decimal places.)
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