Posted by **Jason** on Sunday, April 15, 2012 at 9:09pm.

A private medical clinic wants to estimate the true mean annual income of its patients. The clinic needs to be within $100 of the true mean. The clinic estimates that the true population standard deviation is around $2,100. If the confidence level is 95%, find the required sample size in order to meet the desired accuracy.

- Statistics -
**MathGuru**, Monday, April 16, 2012 at 4:45pm
Use a formula to find sample size.

Here is one:

n = [(z-value * sd)/E]^2

...where n = sample size, z-value will be 1.96 using a z-table to represent the 95% confidence interval, sd = 2100, E = 100, ^2 means squared, and * means to multiply.

Plug the values into the formula and finish the calculation. Round your answer to the next highest whole number.

Hope this helps.

- Statistics -
**Anonymous**, Friday, September 21, 2012 at 10:16pm
A population is normally distributed with mean 26.8 and standard deviation 2.5. Find p( 26.8 < x < 29.3 ). (Round your answer to FOUR decimal places.)

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