Posted by Johnson on Sunday, April 15, 2012 at 8:41pm.
I would look at dGo tables in your text, calculate dGo for the reaction, use that to solve for Keq, then explain how the system reacts.
On a much less work scale, the rate at which CH4 and H2S react decreases with time while the rate at which CS2 and H2 react increases with time. There is a point at which the forward reaction and the reverse direction are equal and this is equilibrium. This should serve to get you started.
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