Question

Solve:

3^(2a+3)=7^(a-4)

Please Help and Thank you

Answer 1

3^(2a+3) = 7^(a-4).

(2a+3)*Log3 = (a-4)*Log7.
Divide both sides by Log3:
2a+3 = 1.771(a-4).
2a+3 = 1.771a-7.085.
2a-1.77a = -7.085-3.
0.23a = -10.085.
a = -43.85.