Based on the balanced equation
4Na + O2 → 2Na2O
calculate the number of Na2O formula units formed when 60 Na atoms and 10 O2 molecules react?
Thanks.
To calculate the number of Na2O formula units formed, we need to use the stoichiometric coefficients from the balanced equation and the given quantities of reactants.
The balanced equation tells us that 4 moles of Na react with 1 mole of O2 to produce 2 moles of Na2O. Since the molar ratio is constant, we can use this ratio to calculate the number of Na2O formula units.
First, let's convert the given quantities into moles:
60 Na atoms = (60 atoms) / (Avogadro's number) ≈ (60 atoms) / (6.022 x 10^23 atoms/mol) = 9.96 x 10^-23 moles of Na
10 O2 molecules = 10 molecules / 2 ≈ 5 moles of O2
Now, let's compare the ratios:
From the balanced equation, we know that 4 moles of Na react with 1 mole of O2 to produce 2 moles of Na2O.
Since we have 9.96 x 10^-23 moles of Na and 5 moles of O2, we can determine the limiting reactant (which one will be completely used up in the reaction):
In this case, O2 is the limiting reactant because we have more moles of O2 (5) than moles of Na (9.96 x 10^-23).
Using the limiting reactant (O2) as the basis for the calculation, we can determine the number of moles of Na2O produced:
Using the molar ratio from the balanced equation, we have:
1 mole of O2 produces 2 moles of Na2O
So, 5 moles of O2 will produce (5 moles) x (2 moles Na2O / 1 mole O2) = 10 moles of Na2O
Finally, we can convert moles of Na2O into formula units:
1 mole of Na2O contains Avogadro's number of formula units (6.022 x 10^23 formula units/mol).
Therefore, (10 moles) x (6.022 x 10^23 formula units/mol) = 6.022 x 10^24 formula units of Na2O.
So, when 60 Na atoms and 10 O2 molecules react, the number of Na2O formula units formed is approximately 6.022 x 10^24 units.