One bag contains 2 green marbles and 4 white marbles and a second bag contains 3 green marbles and 1 white marble. If Jon randomly draws one marble from each bag what is the probability that they are both green?

To solve this problem, we need to calculate the probability of drawing a green marble from the first bag and a green marble from the second bag, and then multiply those probabilities together.

Let's start with the first bag. It contains 2 green marbles and 4 white marbles. The total number of marbles in the bag is 2 + 4 = 6.

The probability of drawing a green marble from the first bag can be calculated as the number of green marbles in the bag divided by the total number of marbles: 2/6 = 1/3.

Now let's move on to the second bag. It contains 3 green marbles and 1 white marble. The total number of marbles in the bag is 3 + 1 = 4.

The probability of drawing a green marble from the second bag can be calculated as the number of green marbles in the bag divided by the total number of marbles: 3/4.

To find the probability of drawing a green marble from both bags, we need to multiply the probabilities together: (1/3) * (3/4) = 1/4.

Therefore, the probability that Jon randomly draws a green marble from both bags is 1/4, or 0.25, which is equivalent to 25%.

it will be 1/2