whats the product of -8x^2y and-2xy^3? use law of exponents to find the product. show your work. please helppp
8 x ^ 2 * y * ( - 2 x * y ^ 3 ) =
8 * ( - 2 ) * x ^ 2 * x * y * y ^ 3 =
- 16 x ^ 3 y ^ 4
To find the product of -8x^2y and -2xy^3, you can use the law of exponents, specifically the product rule which states that when multiplying two terms with the same base, you can add their exponents.
-8x^2y * -2xy^3
Multiplying the coefficients:
-8 * (-2) = 16
Applying the exponent rule for x:
x^2 * x = x^(2+1) = x^3
Applying the exponent rule for y:
y * y^3 = y^(1+3) = y^4
Putting it together, the product becomes:
16x^3y^4
To find the product of -8x^2y and -2xy^3 using the law of exponents, we can apply the multiplication property of exponents which states that when the same base is being multiplied, we add the exponents.
The given expression is: -8x^2y * -2xy^3
We can begin by multiplying the coefficients (-8 and -2), followed by multiplying the variables with the same base (x and y) by adding their exponents.
Coefficient calculation:
-8 * -2 = 16
Variable calculation:
x^2 * x = x^(2+1) = x^3
y * y^3 = y^(1+3) = y^4
Therefore, the product of -8x^2y and -2xy^3 is 16x^3y^4.
If you have any further questions, please feel free to ask!