Homework Help: physic

Posted by cn on Sunday, April 15, 2012 at 4:47pm.

A roller coaster car (390 kg) moves from A (5.00 m above the ground) to B (19.0 m above the ground). Two nonconservative forces are present: friction does -2.00 104 J of work on the car, and a chain mechanism does +3.00 104 J of work to help the car up a long climb. What is the change in the car's kinetic energy, ÄKE = KEf − KE0, from A to B?

physic - Elena, Sunday, April 15, 2012 at 5:14pm
The change in potential energy is
Δ PE = mgh2-mgh1 = 390•9.8•(19 -5) = 53508J
If the change in car's kinetic energy is ΔKE, then
ΔKE + 3.0•10^4 - 2.0•10^4 = Δ PE
ΔKE = 53508 -10000 = 43508 J

Answer this Question

Related Questions

physics - A roller coaster (425 kg) moves from A (5.00 m above the ground) to B...
physics - A roller coaster (375. kg) moves from A (5.00 m above the ground) to B...
Physics - A roller coaster (340. kg) moves from A (5.00 m above the ground) to B...
Physics - A roller coaster (491 kg) moves from A (1.09 m above the ground) to B...
Physics(Please respond) - 1) A roller coaster (398 kg) moves from A (3.82 m ...
Physics - A roller-coaster car with a mass of 500 kg starts at rest from point A...
Physics - A roller coaster is initially at a height of 40 m above the ground and...
Physics - A roller coaster is initially at a height of 40 m above the ground and...
Physics - A roller coaster is initially at a height of 40 m above the ground and...
Physics - A roller coaster is initially at a height of 40 m above the ground and...

For Further Reading

First Name:
School Subject:
Answer: