Posted by **emilia** on Sunday, April 15, 2012 at 2:54pm.

I posted this question earlier and thank you for respnding, but the answer you give me was incorrect. I try looking at hw you solve and cant find the mistake but when when I check your answer it said it was wrong. Can you please look over it again, I greatly appreciate it

a toy rocket moving vertically upward passes by a 2.2m- high window whose sill is 7.0m above the ground. the rocket takes 0.17s to travel the 2.2m height of the wondow

part a): what was the launch speed of the rocket ? assume the propellant is burned very quickly at blastoff

part b) how high will the rocket go ?

- @ elena - intro to physics -
**Elena**, Sunday, April 15, 2012 at 3:24pm
What is the correct answer? I'll try to understand where is the mistake.

- @ elena - intro to physics -
**Elena**, Sunday, April 15, 2012 at 3:51pm
I‘ve found the mistake

h(o) = v(o)•t - g•t^2/2,

2 h(o) = 2 v(o)•t - g•t^2

v(o) = h(o) /t +gt/2 = 2.2/0.17 + 9.8•0.17/2 = 13.77 m/s.

Then try to calculate yourself…

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