math
posted by rohit on .
if x3+ax2bx+10 is divisible by x23x+2 .find the value of a and b

since x^2  3x + 2 = (x2)(x1)
so x^3 + ax^2 bx + 10 must be divisible by both
x2 and x1
let f(x) = x^3 + ax^2 bx + 10
f(2) = 5 + 4a  2b + 10 = 0 > 4a  2b = 15
f(1) = 1 + a  b + 10 > ab = 11 or a = b11
sub 2nd into 1st
4(b11)  2b = 15
4b  44  2b = 15
2b = 29
b = 29/2
then a = 29/2  11 = 7/2