Posted by **Charlie** on Sunday, April 15, 2012 at 8:59am.

An aquarium filled with water has flat glass sides whose index of refraction is 1.48. A beam of light from outside the aquarium strikes the glass at a 43.5º angle to the perpendicular . The angle this light ray enters the glass is 27.7º, what is the angle of this light ray when it enters the water?

- Physics -
**Elena**, Sunday, April 15, 2012 at 12:08pm
The angle in the glass ( r ) related to the angle of incidence (i) as

sin i/sin r = n2/n1

sin r = n1•sin i/n2 = 1•sin 43.5/1.48 = =0.465

r = arcsin 0.465= 27.7degr.

Because the surfaces are parallel, the refraction angle from the first surface is the incident angle at the second surface.

sin r/sin φ =n3/n2

sin φ = n2•sin r/n3 =1.48•0.465/1.33 =0.517,

φ = arcsin 0.517 =31.16 degr.

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