posted by 18 on .
Just as a car tops a 51 meter high hill with a speed of 84 km/h it runs out of gas and coasts from there, without friction or drag. How high, to the nearest meter, will the car coast up the next hill?
v =84 km/h= 23.33 m/s.
mv^2/2+mgh = mgH.
H = h +v^2/2g =51 +27.78 =78.78 m.