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July 30, 2014

July 30, 2014

Posted by **lindsay** on Sunday, April 15, 2012 at 2:52am.

f(x)=∫(0,x) t^3+2t^2+2dt, and find f"(x).

my answer was:

f'(x)=x^3+x^2+2

f"(x)=x^4/4 + 2x^3/3 + 2x

it said its wrong.

- COLLEGE CALCULUS. HELP! -
**Steve**, Sunday, April 15, 2012 at 6:33amwell, yeah.

f'' = 3x^2 + 2x

why did you take the antiderivative to go from f' to f''?

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