Two pellets, each with a charge of 0.80 microcoulomb (8.0×10−7 C), are located 4.0 cm (4.0×10−2 m) apart. Find the electric force between them.

Coulomb’s law

F = k•q1•q2/r^2 =k•q^2/r^2 ,
k = 9•10^9 N•m^2/C

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To find the electric force between two charged particles, you can use Coulomb's Law. Coulomb's Law states that the electric force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:

F = k * (|q1| * |q2|) / r^2

Where:
F is the electric force between the charges,
k is the electrostatic constant (9.0 × 10^9 N.m^2/C^2),
|q1| and |q2| are the magnitudes (absolute values) of the charges, and
r is the distance between the charges.

In this case, both charges are 0.80 microcoulomb (8.0 × 10^(-7) C) and the distance between them is 4.0 cm (4.0 × 10^(-2) m). Plugging these values into the formula, we get:

F = (9.0 × 10^9 N.m^2/C^2) * (8.0 × 10^(-7) C) * (8.0 × 10^(-7) C) / (4.0 × 10^(-2) m)^2

Now, let's calculate it step by step:
1. Multiply the magnitudes of the charges:
|q1| * |q2| = (8.0 × 10^(-7) C) * (8.0 × 10^(-7) C)
= 6.4 × 10^(-13) C^2

2. Square the distance between the charges:
r^2 = (4.0 × 10^(-2) m)^2
= 1.6 × 10^(-3) m^2

3. Plug the values into the formula and calculate the electric force:
F = (9.0 × 10^9 N.m^2/C^2) * (6.4 × 10^(-13) C^2) / (1.6 × 10^(-3) m^2)
= 3.6 N

Therefore, the electric force between the two charged pellets is 3.6 Newtons.