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Posted by on Saturday, April 14, 2012 at 8:54pm.

Calculate the pH of an aqueous solution of 0.15 M potassium carbonate.

I know that pH = -log(H30+) but I am not sure how to start this problem.

  • Chemistry(Please help) - , Saturday, April 14, 2012 at 11:09pm

    Hydrolyze the CO3^2-.
    CO3^- + HOH ==> HCO3^- + OH^-
    Do an ICE chart, Kb = Kw/k2 for H2CO3.

  • Chemistry(Please help) - , Sunday, April 15, 2012 at 4:22pm

    so for kb I do 1e-14/.15?

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