C3H8+5O2=3CO2+H2O How many liters of propaine (d=0.585g/ml) will produce 1.25L of water (d=1.00g/mL)?
First you balance the equation.
C3H8 + 5O2 ==> 3CO2 + 4H2O
1.25L H2O with density 1.00 g/mL = 1,250 grams.
mols H2O = grams/molar mass = ?
Convert to mols C3H8 using the coefficients in the balanced equation.
?mol H2O x (1 mol C3H8/4 mols H2O) = xx mol C3H8. Then g = mols C3H8 x molar mass. Convert to mL using the density.
To solve this problem, we need to use the concept of stoichiometry and the molar mass of propane (C3H8). Here's the step-by-step explanation:
Step 1: Find the molar mass of propane (C3H8).
The molar mass can be calculated by summing up the atomic masses of each element in the compound. Carbon (C) has an atomic mass of 12.01 g/mol, and hydrogen (H) has an atomic mass of 1.01 g/mol.
Molar mass of propane (C3H8) = (3 * molar mass of carbon) + (8 * molar mass of hydrogen)
= (3 * 12.01 g/mol) + (8 * 1.01 g/mol)
= 36.03 g/mol + 8.08 g/mol
= 44.11 g/mol
Step 2: Calculate the number of moles of water produced.
We know that the volume of water produced is 1.25 L. However, we need to convert this volume to moles to perform further calculations. To do this, we'll use the density of water, which is 1.00 g/mL.
Given that we have 1.25 L of water, we can calculate the mass of water using its density:
Mass of water = Volume of water * Density of water
= 1.25 L * 1.00 g/mL
= 1.25 g
Next, we'll convert the mass of water to moles using the molar mass of water. The molar mass of water (H2O) is the sum of the molar masses of hydrogen (H) and oxygen (O).
Molar mass of water (H2O) = (2 * molar mass of hydrogen) + (1 * molar mass of oxygen)
= (2 * 1.01 g/mol) + (1 * 16.00 g/mol)
= 2.02 g/mol + 16.00 g/mol
= 18.02 g/mol
Number of moles of water = Mass of water / Molar mass of water
= 1.25 g / 18.02 g/mol
≈ 0.0694 mol (rounded to four decimal places)
Step 3: Use the balanced chemical equation to find the moles of propane.
From the balanced equation, we know that the ratio of moles of propane to moles of water is 1:1. This means that the moles of propane (C3H8) will be equal to the moles of water.
Number of moles of propane (C3H8) = Number of moles of water
≈ 0.0694 mol
Step 4: Convert the moles of propane to the volume of propane.
To convert the moles of propane (C3H8) to its volume, we first convert moles to grams using the molar mass of propane, and then convert grams to milliliters using the given density of propane.
Mass of propane = Number of moles of propane * Molar mass of propane (C3H8)
= 0.0694 mol * 44.11 g/mol
≈ 3.059 g (rounded to three decimal places)
Next, we use the density of propane (d=0.585 g/mL) to convert the mass of propane to volume:
Volume of propane = Mass of propane / Density of propane
= 3.059 g / 0.585 g/mL
≈ 5.23 mL (rounded to two decimal places)
Therefore, approximately 5.23 liters of propane will produce 1.25 liters of water.